In orthogonal machining operation, the chip thickness and the uncut chip thickness are equal to 0.45mm. If the tool rake and is 0 deg. The shear plane angle is
A
45o
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B
30o
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C
18o
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D
60o
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Solution
The correct option is A45o t1=t2=0.45 ⇒r=t1t2=1 α=0 ϕ=tan−1(1cos0o1−1×sin0o) =tan−1(1)=45o