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Standard XII

Physics

Ideal Gas Equation

In outer spac...

Question

In outer space there are 10 molecules per cm $^{3}$ on an average and the temperature there is 3K. The average pressure of this light gas is

10^{5} N m^{- 2}

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5 \times 10^{- 14} N m^{- 2}

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0.4 \times 10^{- 16} N m^{- 2}

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4.14 \times 10^{- 16} N m^{- 2}

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Solution

The correct option is D $4.14 \times 10^{- 16} N m^{- 2}$
$P = \frac{n K T}{V} = \frac{10 \times 1.38 \times 10^{- 23} \times 3}{10^{- 6}}$
$= 4.14 \times 10^{- 16} N m^{- 2}$

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In outer space there are 10 molecules per cm3 on an average and the temperature there is 3K. The average pressure of this light gas is

The correct option is D 4.14×10−16Nm−2P=nKTV=10×1.38×10−23×310−6=4.14×10−16Nm−2

In outer space there are 10 molecules per cm $^{3}$ on an average and the temperature there is 3K. The average pressure of this light gas is

The correct option is D $4.14 \times 10^{- 16} N m^{- 2}$
$P = \frac{n K T}{V} = \frac{10 \times 1.38 \times 10^{- 23} \times 3}{10^{- 6}}$
$= 4.14 \times 10^{- 16} N m^{- 2}$