In parallelogram ABCD, AP and CQ are perpendicular to diagonal BD.
It can be proved that ΔAPB ≅ ΔCQD.
True
In ΔAPB and ΔCQD,
AB=CD Opposite sides of a parallelogram
∠ ABP=∠ CDQ
Alternate angles
∠APB = ∠CQD both are right angles
∴ Δ APB ≅ Δ CQD using AAS criterion