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Standard IX

Mathematics

Theorem 1: Parallelograms

In parallelog...

Question

In parallelogram ABCD, CB $=$ 6cm, AF $=$ 8cm. If AB $=$ 12 cm, then CE equals

28 cm

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2 cm

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4 cm

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14 cm

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Solution

The correct option is C 4 cm
$A r (A B C D) = B C \times A F = b \times h = 6 \times 8 = 48 {c m}^{2} A r (A B C D) = A B \times C E = 12 \times C E = 48 o r C E = 4 c m$

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In parallelogram ABCD, CB = 6cm, AF = 8cm. If AB =12 cm, then CE equals

The correct option is C 4 cmAr(ABCD)=BC×AF=b×h=6×8=48cm2Ar(ABCD)=AB×CE=12×CE=48orCE=4cm

In parallelogram ABCD, CB $=$ 6cm, AF $=$ 8cm. If AB $=$ 12 cm, then CE equals

The correct option is C 4 cm
$A r (A B C D) = B C \times A F = b \times h = 6 \times 8 = 48 {c m}^{2} A r (A B C D) = A B \times C E = 12 \times C E = 48 o r C E = 4 c m$