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Question

In parallelogram ABCD if A=(3x20),B=(y+15),C=(x+40), then find the value of x and y .

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Solution

In a ||gm ABCD,

A=(3x20),B=y+15,C=x+40

Now, A=C (Opposite angles of a ||gm)

3x20=x+40
3xx=40+202x=60
x=602=30

and A+B=180 (Sum of the consecutive angles)

3x20+y+15=180
3x+y5=180
3×30+y5=180
905+y=180
y=18090+5=95
x=30,y=95


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