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RHS Rule

In parallelog...

Question

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP=BQ (see the given figure) Show that:

$Δ A Q B ≅ Δ C P D$

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Solution

In $Δ A Q B ≅ Δ C P D$ ,
$∠ A B Q = ∠ C D P$ (Alternate interior angles for AB||CD)
AB=CD (Opposite sides of parallelogram ABCD)
BQ=DP( Given)
$Δ A Q B ≅ Δ C P D$ (Using SAS congruence rule)

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