In ΔAPD and ΔCQB,
∠ADP=∠CBQ (Alternate interior angles)
AD =CB (Opposite sides of parallelogram ABCD)
DP=BQ (Given)
∴ΔAPD≅ΔCQB ( using SAS congruence rule)
As we have proved that triangle APD is congruent to triangle CQB,
So , AP= CQ (CPCT) and
AQ=CP
Since opposite sides In quadrilateral APCQ are equal to each other, APCQ is a parallelogram.