In Parallelogram PQRS- - Q - 4x-5-and - S - 3x-10- Calculate- - Q and - R

In Parallelogram PQRS, Q=(4x 5)^∘ and ∠ S= (3x+10)^∘ Opposite nbsp; ∠ s of parallelogram are equal ∠ Q = ∠ S 4x 5 = 3x + 10 4x 3x = 10 + 5 x = 15 ∠ Q = 4x ...

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Standard IX

Mathematics

Applications of Pair of Equations

In Parallelog...

Question

In Parallelogram PQRS, $∠ Q = (4 x - 5)^{\circ} a n d ∠ S = (3 x + 10)^{\circ} .$ Calculate: $∠ Q a n d ∠ R$

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Solution

In Parallelogram PQRS,
$Q = (4 x - 5)^{\circ} a n d ∠ S = (3 x + 10)^{\circ}$
Opposite $∠ s$ of parallelogram are equal
$∠ Q = ∠ S$
4x - 5 = 3x + 10
4x - 3x = 10 + 5
x = 15
$∠ Q = 4 x - 5 = 4 \times 15 - 5 = 55^{\circ} A l s o ∠ Q + ∠ R = 180^{\circ} 55^{\circ} + ∠ R = 180^{\circ} ∠ R = 180^{\circ} - 55^{\circ} = 125^{\circ}$

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In Parallelogram PQRS, ∠Q=(4x−5)∘and ∠S=(3x+10)∘. Calculate: ∠Q and ∠R

In Parallelogram PQRS, Q=(4x−5)∘ and ∠S=(3x+10)∘ Opposite ∠s of parallelogram are equal ∠Q=∠S 4x - 5 = 3x + 10 4x - 3x = 10 + 5 x = 15 ∠Q=4x−5=4×15−5=55∘Also ∠Q+∠R=180∘55∘+∠R=180∘∠R=180∘−55∘=125∘

In Parallelogram PQRS, $∠ Q = (4 x - 5)^{\circ} a n d ∠ S = (3 x + 10)^{\circ} .$ Calculate: $∠ Q a n d ∠ R$