In pea plant, hybrids obtained as a result of cross between red flowered and white flowered strains, were crossed with the parent having pure red flowers. The progeny of this cross will have

Red flowers only

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

White flower only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Equal number of red and white flower

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Mostly red flower

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Red flowers only
Pure red : RR
Pure white flower : rr
RR $\times$ rr
$F_{1} : R r$
$F_{1}$ hybrid cross with pure red flowered plant(RR)
$R r \times R R$
R R
$F_{2}$ R RR RR
r Rr Rr
All red.
$F_{1} = R r$
$F_{2} = R R, R R, R r, R r$
RR $=$ red
Rr $=$ red
Hence option A is correct.

Suggest Corrections

Similar questions

Q. Hybrid of pure red flowered and white flowered Pea is crossed to pure red flowered plant. The progeny shall be

Q. If hybrid red flowered plants of pea are crossed back to pure red flowered parent, the progeny will show

Q. Pure red flowered and white flowered plants were crossed. It produced 120 offspring with

Q. If, in a plant, red colour of the flower is dominant over white. A cross was made between a plant containing red flower and other with white flower. The cross yielded 50% white flowered plant and 50% red flowered plant. The genotype of the parent with red flower is:

In a plant, the red colour of the flower is dominant over white. A cross was made between a plant containing red flower and other with white flower. The cross yielded 50% white-flowered plant and 50% red flowered plant. The trait of the parent with the red flower has:

Join BYJU'S Learning Program

In pea plant, hybrids obtained as a result of cross between red flowered and white flowered strains, were crossed with the parent having pure red flowers. The progeny of this cross will have

The correct option is A Red flowers onlyPure red : RRPure white flower : rrRR × rrF1:RrF1 hybrid cross with pure red flowered plant(RR)Rr×RR R RF2 R RR RR r Rr RrAll red.F1=RrF2=RR,RR,Rr,RrRR=redRr=redHence option A is correct.