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Question

In PERT, the distribution of activity time is assumed to be

A
Normal
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B
Gamma
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C
Exponential
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D
Beta
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Solution

The correct option is D Beta
In PERT, activity, time is assumed to be Beta distribution and project is assumed to be normal distribution.


Where, a or t0= optimistic time

tE or μ= mean time or expected time

tm or μ= most likely time

tp or b= pessimistic time

Expected or mean time,

tE or μ=t0+4tm+tp6=a+4m+b6

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