Question

In photoelectric effect the slope of straight line graph between stopping potential $4\left(V_0\right)$ and frequency of incident light (V) gives:

• A. Charge on electron
• B. Work function of emitter
• C. Planek's Constant
• D. ratio of Planek's constant to charge on electrons

Answer 1

The correct option is A Charge on electron

We know that

By photoelectric equation we have

$h\nu =h{\nu }_o+K.E$

$h\nu =W+e{V}_o\to$shapping potential

$e{V}_o=h\nu -W\Rightarrow V_o=\left(\frac{h}{e}\right)\nu +\left(\frac{-W}{e}\right)$

$y=mx+C$

Compairing two equation $\Rightarrow m=\frac{h}{c}$

Slope is ratio of planck's constant to charge of electrons