Question

In photoelectric effect, the slope of the straight line graph between stopping potential and frequency of the incident light gives the ratio of Planck's constant to

• A. Charge of electron
• B. Work function
• C. Photoelectric current
• D. K.E. of electron

Answer 1

Answer: (A)

Charge of electron

$hv=h{v}_0+K.E$
at stopping potential K.E$=$eV
$\Rightarrow hv=h{v}_0+eV$

$V=\frac{h}{e}(v-v_0)$

The slope of graph b/w stopping potential and frequency is $\frac{h}{e}$, where e is charge of electron.