In photoelectric emission, the energy of the emitted electrons is:
A
Larger than that of the incident photons
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B
Smaller than that of the incident photons
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C
Same at that of the incident photons
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D
Proportional to the intensity of the incident light
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Solution
The correct option is D Smaller than that of the incident photons hv=hv0+K.E Energy of emitted electrons is less than hv as part of it is lost for the work function of metal.