In pne Krebs cycle, decarboxylation takes place at .......... steps.
A
Five
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B
Four
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C
Three
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D
Two
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Solution
The correct option is C Two In single Krebs cycle decarboxylation takes place at following two steps-
1. First oxidative decarboxylation takes place at fourth step where isocitrate gives off a pair of hydrogen atoms (oxidation) and a molecule of carbon-di-oxide (decarboxylation) and becomes 5-carbon α- ketoglutarate.
2. Second oxidative decarboxylation takes place at fifth step where coenzyme-A reacts with α- ketoglutarateforming 4-carbonsuccinyl-coenzyme A and releasing carbon-di-oxide and a pair of hydrogen atoms.