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V-t to a-t Graph

In position A...

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In position A kinetic energy of a particle is 60 J and potential energy is-20 J. In position B, kinetic energy is 100 J and potential energy is 40 J. Then, in moving the particle from A to B. Find a) work done by conservative forces b) work done by external forces c) net work done by all the forcs

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Q. In position A, the K.E energy of a particle is 60 J and P.E is -20 J. In position B for the same particle, the K.E is 100 J and P.E is 40 J. Then which one of the following is correct in moving the particle from A to B ?

Q. A body is displaced from position

A

B

. Kinetic and potential energies of the body at positions

A

B

K_{A} = 70 J, U_{A} = - 50 J, K_{B} = - 20 J

U_{B} = 30 J

Q. A body is freely moving under the action of a conservative force. If the work done by this conservative force is 'a', change in kinetic energy 'b' & magnitude of change in potential energy is 'c', then

Q. Assertion :The change in kinetic energy of a particle is equal to the work done on it by the net force. Reason: Change in kinetic energy of particle is equal to the work done only in case of a system of one particle.

Q. A particle is taken from point A to point B under the influence of a force field. Now it is taken back from B to A and it is observed that the work done in taking the particle from A to B is not equal to the work done in taking it from B to A. If

W_{n c}

W_{c}

are work done by non-conservative and conservative forces present in the system, respectively,

Δ U

is the change in potential energy and

Δ K

is the change in kinetic energy, then

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