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Question
In position A, the K.E energy of a particle is 60 J and P.E is -20 J. In position B for the same particle, the K.E is 100 J and P.E is 40 J. Then which one of the following is correct in moving the particle from A to B ?
In position A, the K.E energy of a particle is 60 J and P.E is -20 J. In position B for the same particle, the K.E is 100 J and P.E is 40 J. Then which one of the following is correct in moving the particle from A to B ?
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Solution
The correct option is C Net work done by all the forces is 40 J
It is known from theory that
Work done by conservative forces =Ui−Uf
Work done by external forces =Ef−Ei
Net work done by all forces
=Kf−Ki
So Work done by conservative forces =Ui−Uf=−20−40=−60 J
So Work done by external forces =Ef−Ei=140−40=100 J
and Net work done by all forces
=Kf−Ki=100−60=40 J
It is known from theory that
Work done by conservative forces =Ui−Uf
Work done by external forces =Ef−Ei
Net work done by all forces
=Kf−Ki
So Work done by conservative forces =Ui−Uf=−20−40=−60 J
So Work done by external forces =Ef−Ei=140−40=100 J
and Net work done by all forces
=Kf−Ki=100−60=40 J
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