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Incenter and Construction of Incircle in a Triangle

In ∆ PQR PQ> ...

Question

In ∆ PQR PQ> PR and PS is angle bisector of angle P then: (1) PS=PR (2) PSPS (4) PQ

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Solution

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The diagonal PR of a quadrilateral PQRS bisects the angles P and R, then

∠ P Q R = ∠ P R S

P Q R

P R S

P R = 8 c m, P S = 4 c m

P Q

P R > P Q

P S

∠ Q P R

∠ P S R > ∠ P S Q

P S

∠ Q P R

△ P Q R

\frac{Q S}{S R} = \frac{P Q}{P R}

P S

∠ Q P R

Δ P Q R .

\frac{Q S}{S R} = \frac{P Q}{P R} .

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