CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Median of Triangle

In Δ PQR , ∠ ...

Question

In $∆$ PQR, $∠$ Q = 90 $°$ and seg QS is the median. QS = 7.4 cm, find PR.

Open in App

Solution

Construction:
Draw a circumcircle of $△$ PQR.
We know:
$∠ PQR = 90 °$
Also, we know that the angle in a semicircle is 90°.
Hence, PR is the diameter of the circle .
QS, which is equal to 7.4 cm, is the radius of the circle.
PR = 2(Radius)
= 2(7.4)
= 14.8 cm

Suggest Corrections

thumbs-up

0

Similar questions

Δ P Q R, ∠ Q = 90^{\circ}

Q S

is the median. If

Q S = 7.4

P R

∆

∠

Q = 90^°, PQ = 12, QR = 5 and QS is a median. Find l(QS).

Δ P Q R, ∠ P Q R = 90^{o}

Q S ⊥

P R

P S = 4

S R = 9

Q S

△ P Q R, ∠ Q = 90^{\circ}

, PQ = 12 units, QR = 5 units and QS is a median. Find l(QS).

Δ A B C

Δ P Q R

∠ A B C ≅ ∠ P Q R

B D

Q S

are angle bisector. If

\frac{l (A D)}{l (P S)} = \frac{l (D C)}{l (S R)}

Δ A B C \sim Δ P Q R

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Median of Triangle

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Median of Triangle

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon