Question

In presence of a catalyst, the activation energy is lowered by 3 kcal at ${27}^{o}C$. Hence, the rate of reaction will increase by:

• A. 32 times
• B. 243 times
• C. 3 times
• D. 48 times

Answer 1

The correct option is C 3 times

$K={Ae}^{\frac{-Ea}{RT}}$

So Ratio, $\frac{K_2}{K_1}=e^{\frac{(E{a}_2-E{a}_1)}{RT}}$

$\frac{K_2}{K_1}$=$e^{\frac{(3\times 1000)}{(8.314\times 300)}}$=$e^{3000/2494}$ = $e^{1.2}$ = $3.3$

Nearly 3 times.