Question

In Q. No. 24, Maximum of z occurs at
(a) (5, 0)
(b) (6, 5)
(c) (6, 8)
(d) (4, 10)

Answer 1

Points	Value of z
(0, 0)	0
(0, 8)	−32
(5, 0)	15
(4, 10)	−28
(6, 8)	−14

For z = 3x − 4y
z(0, 0) = 3(0) − 4(0) = 0
z(0, 8) = 3(0) − 4(8) = −32
z(5, 0) = 3(5) − 4(0) = 15
z(4, 10) = 3(4) − 4(10) = 12 − 40 = − 28
z(6, 8) = 3(6) − 4(8) = 18 − 32 = −14
and z(6, 5) = 3(6) − 4(5) = 18 − 20 = −2
∴ Maximum of z occurs at (5, 0)
i.e. Z_max = 15
Hence, the correct answer is option A.