In quadrilateral ABCD, BM and DN are drawn perpendicular to AC such that BM = DN. If BR = 8cm. them BD is

4 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 16 cm
$Δ D N R$ and $Δ B M R$ ;
DN = BM
$∠ D N R = ∠ B M R = 90$
$∠ D R N = ∠ B R M$ (vertically opposite)
So, by AAS criteria
$Δ D N R$ and $Δ B M R$ are congruent
DR = BR = 8 cm
So, BD = 8 + 8 = 16 cm

Suggest Corrections

Similar questions

A B C D, B M

D N

A C

B M = D N

B R = 8 c m

B D

In Fig. BM and DN are both perpendiculars to the segments AC and BM = DN. Prove that AC bisects BD [3 MARKS]

Join BYJU'S Learning Program