Question

In quadrilateral $ABCD,BM$ and $DN$ are drawn perpendicular to $AC$ such that $BM=DN$. If $BR=8cm$, then $BD$ is

• A. $4cm$
• B. $2cm$
• C. $12cm$
• D. $16cm$

Answer 1

The correct option is D $16cm$

$BM=DN$

$BR=3cm$

$△BMR$ & $△DNR$

$BM=DN$

$\angle BRM=\angle NRD$

$\angle BMR=\angle DNR$ ( each ${90}^o$)

by AAS rules

$△BMR\cong △DNR$

$BR=DR=3cm$

$BD=16cm$