In quadrilateral ABCD, if ∠A=60∘ and ∠B:∠C:∠D=2:4:6, then find the measure of ∠C.
A
90∘
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B
100∘
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C
110∘
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D
120∘
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Solution
The correct option is B100∘ Let ∠B=2x,∠C=4xand∠D=6x ∵ Sum o angles in a quadrilateral is 360∘ ∴∠A+∠B+∠C+∠D=360∘ ⇒60∘+2x+4x+6x=360∘ ⇒12x=360∘−60∘ ⇒12x=300∘ ⇒x=25∘ So, ∠C=4x=4×25∘=100∘