In quadrilateral ABCD, M is the mid-point of AC. If area (BCDM) is 20 $c m^{2}$ , then find the area (ABMD). [3 MARKS]

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Solution

Concept : 1 Mark
Application : 1 Mark
Calculation : 1 Mark

BM is the median of $△$ ABC

ar( $△$ ABM) = ar( $△$ BMC)------(1)

DM is the median of $△$ ADC

Similarly, ar( $△$ AMD) = ar( $△$ MCD)------(2)

Adding (1) and (2) ,

ar(ABMD) = ar(BCDM) = 20 $c m^{2}$

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In quadrilateral ABCD, M is the mid-point of AC. If area (BCDM) is 20 cm2, then find the area (ABMD). [3 MARKS]

Concept : 1 Mark Application : 1 Mark Calculation : 1 Mark BM is the median of △ABC ar(△ABM) = ar(△BMC)------(1) DM is the median of △ADC Similarly, ar(△AMD) = ar(△MCD)------(2) Adding (1) and (2) , ar(ABMD) = ar(BCDM) = 20 cm2

In quadrilateral ABCD, M is the mid-point of AC. If area (BCDM) is 20 $c m^{2}$ , then find the area (ABMD). [3 MARKS]

Concept : 1 Mark
Application : 1 Mark
Calculation : 1 Mark

BM is the median of $△$ ABC

ar( $△$ ABM) = ar( $△$ BMC)------(1)

DM is the median of $△$ ADC

Similarly, ar( $△$ AMD) = ar( $△$ MCD)------(2)

Adding (1) and (2) ,

ar(ABMD) = ar(BCDM) = 20 $c m^{2}$