In quadrilateral ABCD,−−→AB=→a,−−→BC=→b,−−→AD=→b−→a. If M is the mid point of −−→BC and N is a point on −−→DM such that −−→DN=45−−−→DM, then −−→AN=
A
15−−→AC
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B
25−−→AC
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C
35−−→AC
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D
45−−→AC
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Solution
The correct option is C35−−→AC Let point A be taken as origin. Then the position vectors of B,C and D are →a,→a+→b and →b−→a respectively.
P.V. of M=→a+→b+→a2=→a+→b2 −−→DN=45−−→DM ⇒−−→DN:−−−→NM=4:1
P.V. of N=4⎛⎝→a+→b2⎞⎠+→b−→a5=35(→a+→b) ⇒−−→AN=35−−→AC