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Question

In quadrilateral ABCD, AB=a, BC=b, AD=ba. If M is the mid point of BC and N is a point on DM such that DN=45−−DM, then AN=

A
15AC
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B
25AC
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C
35AC
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D
45AC
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Solution

The correct option is C 35AC
Let point A be taken as origin. Then the position vectors of B, C and D are a, a+b and ba respectively.
P.V. of M=a+b+a2=a+b2
DN=45DM
DN:−−NM=4:1
P.V. of N=4a+b2+ba5=35(a+b)
AN=35AC

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