Question

Question 03.
In Question 2 above, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

Answer 1

Let the parts of red pigment mix with 1800 mL base be x
$\begin{array}{ccc}Partsofredpigment& 1& x\\ Partsofbase& 75& 1800\end{array}$

Since it is in direct proportion
$\therefore \frac{1}{75}=\frac{x}{1800}\Rightarrow 75\times x=1\times 1800\Rightarrow x=\frac{1\times 1800}{75}=24parts$
Hence, with base 1800 mL, 24 parts red pigment should be mixed.