Question

In Quincke's experiment the sound detected is changed from a maximum to a minimum when the sliding tube is moved through a distance of $2.50cm$ . Find the frequency of sound if the speed of sound in air is $340m{s}^{-2}$

Answer 1

Distance between two maximum to a minimum is given by, $\lambda /4=2.50cm\Rightarrow \lambda =10cm={10}^{-1}m$
We know, $V=n\lambda$
$\Rightarrow n=\frac{V}{\lambda }=\frac{340}{{10}^{-1}}=3400Hz=3.4kHz$.