In R-L-C series circuit, the potential differences across each element is $20 V$ . Now the value of the resistance alone is doubled, then P.D. across R, L and C respectively.

20 V, 10 V, 10 V

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20 V, 20 V, 20 V

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20 V, 40 V, 40 V

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10 V, 20 V, 20 V

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Solution

The correct option is A $20 V, 10 V, 10 V$
Circuit is at resonance ( $V L = V C$ )
∴ circuit is purely resistance
Resistance is doubled, current in the circuit is half the initial value
∴ New current $I^{'} = I / 2$
∴ $V R = 20 V$ (equal to applied voltage earlier)
$V L = 10 V$
$V C = 10 V$

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In R-L-C series circuit, the potential differences across each element is 20V. Now the value of the resistance alone is doubled, then P.D. across R, L and C respectively.

The correct option is A 20V,10V,10V Circuit is at resonance (VL=VC)∴ circuit is purely resistanceResistance is doubled, current in the circuit is half the initial value∴ New current I′=I/2∴ VR=20V (equal to applied voltage earlier) VL=10V VC=10V

In R-L-C series circuit, the potential differences across each element is $20 V$ . Now the value of the resistance alone is doubled, then P.D. across R, L and C respectively.

The correct option is A $20 V, 10 V, 10 V$
Circuit is at resonance ( $V L = V C$ )
∴ circuit is purely resistance
Resistance is doubled, current in the circuit is half the initial value
∴ New current $I^{'} = I / 2$
∴ $V R = 20 V$ (equal to applied voltage earlier)
$V L = 10 V$
$V C = 10 V$