In rabbits, black skin (B) is dominant over brown skin (b) and short hair (S) is dominant over long hair (s). If a homozygous black skin, short-haired male is crossed with a homozygous brown skin, long-haired female, all $F_{1}$ offspring are heterozygous black and short-haired. What would be the percentage of the homozygous black skin, short-haired offspring, if a male and female of $F_{1}$ generation are made to breed?

6.25%

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12.5%

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18.75%

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50%

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Solution

The correct option is A 6.25%
F1: BbSs × BbSs

Gametes: BS, Bs, bS, bs

Punnett square:

Phenotypes:
Black skin and Short hair - 9
Brown skin and Short hair - 3
Black skin and Long hair - 3
Brown skin and Long hair - 1

(Homozygous black skin short hair $\div$ Total number of offspring) $\times$ 100
⇒ (1 ∕ 16) × 100 = 6.25%

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Calculation of Phenotypic and Genotypic Ratios

Standard XIII Biology

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