Question

In radians ${47}^{\circ }{25}^{\prime }36"$ is $\frac{3557}{13500}{\pi }^c$.If true enter 1 else 0.

Answer 1

${47}^{\circ }{25}^{\prime }{\left(\frac{36}{60}\right)}^{\prime }$
$={47}^{\circ }{\left(25\frac{3}{5}\right)}^{\prime }$
$={47}^{\circ }\left(\frac{128}{5}\right)$
$={47}^{\circ }{(\frac{128}{5}\times \frac{1}{60})}^{\circ }$
$={\left(47\frac{32}{75}\right)}^{\circ }$
$={\left(\frac{3557}{75}\right)}^{\circ }$
$=\frac{3557}{75}\times \frac{{\pi }^c}{180}$
$=\frac{3557}{13500}{\pi }^c.$