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Question

In radioactive reaction AZXAZ+1X1AZ+2X2A4ZX3A4Z+1X4. Successive emission of particles is?

A
β,β,β,α
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B
β,β,β+,α
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C
β,β,α,α
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D
β,β,α,β
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Solution

The correct option is D β,β,α,β
We know that mass number and atomic number of the parent nucleus decrease by 4 units and 2 units in each alpha decay. Whereas mass number remains the same and atomic number of parent nucleus increases by 1 unit in each beta minus decay.
Thus order of decay in the above given reaction is
β, β, α, β
So, correct answer is option D.

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