Question

In reaction

$C_6{H}_{5}C{H}_3\underset{Oxidation}{⟶}A\underset{NaOH}{⟶}B\stackrel{Sodalime}{\to }C$

Then 'C' is

• A. C₆H₆
• B. C₆H₅OH
• C. C₆H₅COONa⁺
• D. C₆H₅ONa

Answer 1

The correct option is A C₆H₆

a)
$C_6{H}_{5}C{H}_3\stackrel{\left[O\right]}{\to }\underset{\left[A\right]}{C_6{H}_{5}COOH}\stackrel{NaOH}{\to }$
$\underset{\left[B\right]}{C_6{H}_{5}COONa}\stackrel{NaOH/CaO}{\to }\underset{\left[C\right]}{C_6{H}_6}$