Question

In Redox reaction:
$Fe+HN{O}_3\to Fe(N{O}_3{)}_2+N{H}_{4}N{O}_3+H_{2}O$ the coefficient of $HN{O}_3,Fe(N{O}_3{)}_2,N{H}_{4}N{O}_3$ is:

• A. $1:10:4$
• B. $10:4:1$
• C. $4:10:4$
• D. $4:1:4$

Answer 1

The correct option is B $10:4:1$

After balancing the equation, we get

$4Fe+10HN{O}_3\to 4Fe(N{O}_3{)}_2+N{H}_{4}N{O}_3+3H_{2}O$

Therefore, Ratio of $HN{O}_3,Fe(N{O}_3{)}_{2}andN{H}_{4}N{O}_3$is :

10:4:1.

Hence, Option B is correct.