In Reimer Tiemann reaction dichlorocarbene acts as:

nucleophile

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electrophile

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free radical

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all of these

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Solution

The correct option is C electrophile
Reimer Tiemann reaction is an electrophile substitution reaction.
The first step is:
$C H C l_{3} + O H^{-} ⇌ H_{2} O + C^{-} C l_{3} \to: C C l_{2} + C l^{-}$
Dichlorocarbene contains a sextet of electron and thus is a strong electrophile.

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