Question

In right-angled triangle $ABC;B={90}^{\circ }$. Find the magnitude of angle $A$, if:
$BC$ is $\sqrt{3}$ times of $AB$.

Answer 1

Given, $\angle ABC={90}^{\circ }$, $\sqrt{3}AB=BC$
Now, $\tan A=\frac{P}{B}=\frac{BC}{AB}=\frac{\sqrt{3}\times AB}{AB}$

$\tan A=\sqrt{3}$

$\tan A=\tan 60$

$A={60}^{\circ }$