Question

In right-angled triangle $ABC;\angle B={90}^{\circ }$, then find the magnitude of angle $A$, if AB is $\sqrt{3}$ times of $BC$.

Answer 1

Given, $\angle ABC={90}^{\circ }$, $AB=\sqrt{3}BC$
Now, $\tan A=\frac{P}{B}=\frac{BC}{AB}=\frac{BC}{\sqrt{3}BC}$

$\tan A=\frac{1}{\sqrt{3}}$

$\tan A=\tan 30$

$A={30}^{\circ }$