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Formation of NaCl Lattice

In rock salt ...

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In rock salt structure if coordination number is 6 then why will the sodium ions be present in the octahedral voids and why chloride ions will hv ccp lattice

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In which of the following structures coordination number for cations and anions in the packed structure will be same ?

(a) $C l^{-}$ ions form fcc lattice and $N a^{+}$ ions occupy all octahedral voids of the unit cell

(b) $C a^{2 +}$ ions form fcc lattice and $F^{-}$ ions occupy all the eight tetrahedral voids of the unit cell

(c) $O^{2 -}$ ions form fcc lattice and $N a^{+}$ ions occupy all the eight tetrahedral voids of

(d) $S^{2 -}$ ions form fcc lattice and $Z n^{2 +}$ ions go into alternate tetrahedral voids of the unit cell

In fluorite structure (CaF₂)

Assertion: In the rock salt type structure, all the octahedral voids are occupied by

N a^{+}

ions.
Reason: Number of octahedral voids

=

C l^{-}

ions in the packing.

Q. For a crystal of sodium chloride, state:
(i) The type of lattice in which it crystallizes.
(ii) The coordination number of each sodium ion and chloride ion in the crystal lattice.
(iii) The number of sodium ions and chloride ions present in a unit cell of sodium chloride.
(iv) The structural arrangement of the sodium chloride crystal.

Q. The tetrahedral voids formed by ccp arrangement of

C l^{-}

ions in rock salt structure are:

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