Question

In Rutherford experiment , number of particles scattered at ${90}^0$ angle are x per second . number of particles scattered oper second at angle $0^0$ is

• A. x
• B. 4 x
• C. 8 x
• D. 16 x

Answer 1

The correct option is B 4 x

No of particles scattered in directly proportional to

the cosec of ${\left(\frac{\theta }{2}\right)}^4$

here $\theta$ in scattering angle

$\frac{N_{final}}{N_{initial}}=\frac{cosec{\left(\frac{60}{2}\right)}^4}{cosec{\left(\frac{90}{2}\right)}^4}=\frac{N_{final}}{x}=\frac{2^4}{(\sqrt{2}{)}^4}$

$\therefore N_{final}=4x$