Question

In rutherford's experiment,number of particles scattered at ${90}^o$ angle are $x$ per second. Number particles scattered per second at angle ${60}^o$ is:

• A. $2x$
• B. $4x$
• C. $8x$
• D. $16x$

Answer 1

The correct option is A $2x$

$\frac{x}{N}=\frac{{\left(\frac{1}{2}\right)}^2}{{\left(\frac{1}{\sqrt{2}}\right)}^2}$
$\therefore \frac{x}{N}=\frac{1}{4}\times 2$
$\therefore N=2x$