In school, 38% of the students are girls. If the number of boys is 1023, find the total strength of the school.

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Solution

It is given that
No. of girls in school $= 38$ %
No. of boys in school = $(100 - 38)$
Consider x as the total strength of school
$62 % o f x = 1023$
It can be written as
$62 / 100 \times x = 1023$
By further calculation
$x = 1023 \times 100 / 62$
So we get
$x = 1023 \times 50 / 31$
$x = 33 \times 50$
$x = 1650$
Therefore, the total strength of the school is 1650.

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In school, 38% of the students are girls. If the number of boys is 1023, find the total strength of the school.

It is given thatNo. of girls in school =38%No. of boys in school = (100−38)Consider x as the total strength of school62%ofx=1023It can be written as62/100×x=1023By further calculationx=1023×100/62So we get x=1023×50/31x=33×50x=1650Therefore, the total strength of the school is 1650.