Question

In self-reduction, the reducing species is _____________.

• A. $S$
• B. $O^{2-}$
• C. $S^{2-}$
• D. $S{O}_2$

Answer 1

The correct option is C $S^{2-}$

$C{u}_{2}S+2C{u}_{2}O\to 6C{u}_{\left(Blistercopper\right)}+S{O}_2\uparrow$

$S^{2-}\to S^{4+}$ is oxidation, i.e., $S^{2-}$ is the reducing agent.

Option C is correct.