In self-reduction, the reduction species is:

S

No worries! We‘ve got your back. Try BYJU‘S free classes today!

O^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S^{2 -}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

S O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $S^{2 -}$
Self-reduction:
$C u_{2} S + 2 C u_{2} O \to 6 C u + S O_{2}$

The oxidation number of sulphur increases from -1 to +4. Therefore, $S^{2 -}$ is the reducing species.

Suggest Corrections

Similar questions

C u F e S_{2}

P b

S n

P b S a i r - \to Δ P b O + S O_{2} C - \to Δ P b + C O_{2}

P b S a i r - \to Δ P b O + P b S Δ - \to P b + S O_{2}

Join BYJU'S Learning Program