Question

In series $L-C-R$ circuit voltage drop across resistance is $8V$, across inductor is $6V$ and across capacitor is $12V$. Then

• A. Voltage of the source will be leading in the circuit.
• B. Voltage drop across each element will be less than the applied voltage.
• C. Power factor of the circuit will be $3/4$.
• D. None of the above.

Answer 1

The correct option is D None of the above.

$V=\sqrt{V_R^2+(V_C-V_L{)}^2}=10V$
$V_C>V_L$, hence current leads the voltage.
Power factor $=\cos \varphi =\frac{8}{10}=0.8$