In series with 20 ohm resistor a 5 henry inductor is placed. To the combination an e.m.f. of 5 volt is applied. What will be the rate of increase of current at t = 0.25 sec
A
e
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
e−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
e−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ce−1
i=io(1−e−RtL)⇒didt=io(RL)eRtL=ELeRtL
On putting values didt=1e=e−1.