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Question
In shear cutting operation, a sheet of 5 mm thickness is cut along a length of 200 mm. The cutting blade is 400 mm long (see figure) and zero-shear S=0 is provided on the edge. The ultimate shear strength of the sheet is 100 MPa and penetration to thickness ratio is 0.2. Neglect friction
A shear of 20 mm ( S = 20 mm) is now provided on the blade. Assuming force vs displacement curve to be trapezoidal, the maximum force (in kN) exerted is
In shear cutting operation, a sheet of 5 mm thickness is cut along a length of 200 mm. The cutting blade is 400 mm long (see figure) and zero-shear S=0 is provided on the edge. The ultimate shear strength of the sheet is 100 MPa and penetration to thickness ratio is 0.2. Neglect friction
A shear of 20 mm ( S = 20 mm) is now provided on the blade. Assuming force vs displacement curve to be trapezoidal, the maximum force (in kN) exerted is
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Solution
The correct option is B 10
For 400 mm length shear is 20 mm, therefore for 200 mm length it becomes 10 mm. Only 200 mm length is effective.
F=Fmax×KtS=10010×10−3=10kN
For 400 mm length shear is 20 mm, therefore for 200 mm length it becomes 10 mm. Only 200 mm length is effective.
F=Fmax×KtS=10010×10−3=10kN
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