In silicon tetrahalides the Lewis acid strength is maximum for :

S i I_{4}

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S i C l_{4}

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S i B r_{4}

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S i F_{4}

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Solution

The correct option is D $S i F_{4}$
A Lewis acid is an electron pair acceptor. In $S i F_{4}$ , the $S i - F$ bond electrons are attracted towards F while the attraction is the least in $S i - I$ bond. So Si in $S i F_{4}$ is most ready to receive/accept electron pairs and hence $S i F_{4}$ is the strongest Lewis acid.

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Similar questions

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

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N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

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