In sinθ+sin2θ=1, then cos2θ+cos4θ=......
We have,
sinθ+sin2θ=1
We know that
sin2θ=1−cos2θ
Therefore,
sinθ+1−cos2θ=1
sinθ−cos2θ=0
sinθ=cos2θ
Since,
=cos2θ+cos4θ
=sinθ+sin2θ
=1
Hence, the value is 1.