In small balls, each of mass m impact elastically each second on a surface with velocity u, then the force experienced by the surface in one second, will be.

4

mnu

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2

mnu

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1.5

mnu

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0.8

mnu

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Solution

The correct option is D $2$ mnu
Force experienced by the surface is equal to change in momentum in one second.
From Newton's second law of motion, the rate of change of momentum of a body is equal to the external force applied on the body and the change in momentum always takes place in the direction of the force.
Momentum of ball before impact $=$ mu
Momentum after imact $= -$ mu
Change in momentum $=$ mu $- (-$ mu $) = 2$ mu
Change in momentum due to n balls in one second is $= 2$ mnu.
Change of momentum $=$ force experienced per second $= 2$ mnu.

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