In sodium carbonate bead test, chromium salts (green) change coloured bead to :

yellow,

P b C r O_{4}

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yellow,

B a C r O_{4}

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yellow,

{N a}_{2} C r O_{4}

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orange,

{N a}_{2} {C r}_{2} O_{7}

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Solution

The correct option is C yellow, ${N a}_{2} C r O_{4}$
$C r_{2} O_{3} (g r e e n) + 2 N a_{2} C O_{3} + \frac{3}{2} O_{2} \to 2 N a_{2} C r O_{4} (y e l l o w) + 2 C O_{2}$

Sodium chromate formed has yellow color on reaction with $C r^{3 +}$ in sodium carbonate bead test.

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Similar questions

{C r}_{2} O_{3}

N a_{2} C r O_{4} -

K M n O_{4} -

K_{2} M n O_{4}

C r_{2} O_{3}

M n O

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