Question

In solid oxide, ions are arranged in ccp. One-sixth of the tetrahedral voids are occupied by the cations ($A$) while one-third of the octahedral voids are occupied by the cations ($B$). What is the formula of the compound?

• A. $AB{O}_3$
• B. $A_{3}BO$
• C. $A{B}_3{O}_3$
• D. $A_2{B}_{3}O$

Answer 1

The correct option is A $AB{O}_3$

The effective number of oxide ions $=4\left(CCPstructure\right)$

Effective number of cation $A=\frac{1}{6}\times$ No. of Tetrahedral voids $=\frac{1}{6}\times 8=\frac{4}{3}$

Effective number of cation $B=\frac{1}{3}\times$ Octahedral voids $=\frac{1}{3}\times 4=\frac{4}{3}$

Formula is:

$=A_{\frac{4}{3}}{B}_{\frac{4}{3}}{O}_4=AB{O}_3$

Hence, option A is correct.